Express sin32+sin54 as sum or difference.

Hello!


This expression is already a sum of two numbers, `sin(32)` and `sin(54).` Probably you want or express it as a product, or as an expression involving trigonometric functions of sum or difference of the arguments, `32` and `54.`


For this, we need the well-known formula


`sin(x) + sin(y) = 2sin((x+y)/2)cos((x-y)/2),`


which is true for any real `x` and `y.`


For the given numbers it gives us


`sin(32) + sin(54) = 2sin((32+54)/2)cos((32-54)/2) =`


`= 2sin(43)cos(-11)...

Hello!


This expression is already a sum of two numbers, `sin(32)` and `sin(54).` Probably you want or express it as a product, or as an expression involving trigonometric functions of sum or difference of the arguments, `32` and `54.`


For this, we need the well-known formula


`sin(x) + sin(y) = 2sin((x+y)/2)cos((x-y)/2),`


which is true for any real `x` and `y.`


For the given numbers it gives us


`sin(32) + sin(54) = 2sin((32+54)/2)cos((32-54)/2) =`


`= 2sin(43)cos(-11) = 2sin(43)cos(11).`



If you misspelled the expression, and it is actually `sin(32)*sin(54),` then we really can express it as a sum with the help of the formula


`sin(x)sin(y) = 1/2(cos(x-y)-cos(x+y)),`


for the given numbers it is


`sin(32)sin(54) = 1/2(cos(-22)-cos(86)) = 1/2(cos(22)-cos(86)).`


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