Blog: A solution is made by dissolving 20g KCIO3 in 100g H2O at 60C. What are three ways to make this solution saturated?

A solution of $\displaystyle{K}{C}{l}{O}_{{3}}$ is made by dissolving 20g $\displaystyle{K}{C}{I}{O}_{{3}}$ in 100 g of water ( $\displaystyle{H}_{{2}}{O}$ ) at 60C.

A solution is considered saturated when no more of the solute can be dissolved in the solution. Any additional amount of solute added remains undissolved.

There are three ways to saturate the solution that was created.

If the temperature is maintained at 60 C, from the graph it is seen that the solubility of $\displaystyle{K}{C}{L}{O}_{{3}}$ is...

A solution of $\displaystyle{K}{C}{l}{O}_{{3}}$ is made by dissolving 20g $\displaystyle{K}{C}{I}{O}_{{3}}$ in 100 g of water ( $\displaystyle{H}_{{2}}{O}$ ) at 60C.

A solution is considered saturated when no more of the solute can be dissolved in the solution. Any additional amount of solute added remains undissolved.

There are three ways to saturate the solution that was created.

If the temperature is maintained at 60 C, from the graph it is seen that the solubility of $\displaystyle{K}{C}{L}{O}_{{3}}$ is around 25 g/100 g of water. If an additional give grams of $\displaystyle{K}{C}{L}{O}_{{3}}$ is added to the solution, it would be saturated.

At 60 C, a saturated solution has 25 g of $\displaystyle{K}{C}{l}{O}_{{3}}$ for 100 g of water. 20 g of $\displaystyle{K}{C}{l}{O}_{{3}}$ would create a saturated solution with 80 g of water. If the solution is heated to evaporate 20 g of water and then cooled down to 60 C, it would result in a saturated solution.

At 50 C, the solubility of $\displaystyle{K}{C}{l}{O}_{{3}}$ is 20 g per 100 g of water. If the temperature of the initial solution is decreased to 50 C, it would become saturated.